DE Maxx Crosby Named AFC Defensive Player of the Week

Las Vegas Raiders defensive end Maxx Crosby named Week one AFC Defensive Player of the Week.

Las Vegas Raiders defensive end Maxx Crosby is quite literally starting the season off in the best way possible.

In the Week 1 33-27 victory over the Baltimore Ravens, Crosby performed the best of any AFC Defensive player, earning him the AFC Defensive Player of the Week award.

Crosby booked six tackles, four quarterback hits, and two sacks in the Week 1 matchup.

Keep in mind this was against quarterback Lamar Jackson, who won NFL MVP a mere two seasons ago.

Crosby owned a Pro Football Focus pass-rush grade of 93.1, tied for best among all edge rushers in Week 1 of play.

This isn’t Crosby's first time receiving AFC Defensive Player of the Week honors. He did it in Week 11 during his rookie season.

Crosby also won AFC Special Teams Player of the Week honors last year in Week 17.

The only thing Crosby needs to keep doing is exactly what he did in Week 1. He needs to continue being the threat on the field the opposing offense has no answer for.

Tell us what you think when you make sure you like our Facebook Page WHEN YOU CLICK RIGHT HERE.

Want the latest breaking Las Vegas Raiders news delivered straight to your email for FREE? Sign up for the DAILY Raiders Nation newsletter when you CLICK THE FOLLOW button on the main page. Don't miss any of the latest up to the second updates for your Las Vegas Raiders when you follow on Twitter @HondoCarpenter